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(A) To find the number of atoms,use the formula: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}$.$

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$1 \ g$ of butane $(C_4H_{10})$

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(A) To find the number of atoms,use the formula: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}$.$A) \ 1 \ g$ of $C_4H_{10}$: $	ext{molar mass} = 58 \ g/mol$,$	ext{atoms} = \frac{1}{58} 	imes 14 	imes N_A \approx 0.241 \ N_A$.$B) \ 1 \ g$ of $N_2$: $	ext{molar mass} = 28 \ g/mol$,$	ext{atoms} = \frac{1}{28} 	imes 2 	imes N_A \approx 0.071 \ N_A$.$C) \ 1 \ g$ of $Ag$: $	ext{molar mass} = 108 \ g/mol$,$	ext{atoms} = \frac{1}{108} 	imes 1 	imes N_A \approx 0.009 \ N_A$.$D) \ 1 \ g$ of $H_2O$: $	ext{molar mass} = 18 \ g/mol$,$	ext{atoms} = \frac{1}{18} 	imes 3 	imes N_A \approx 0.166 \ N_A$.Comparing the values,$1 \ g$ of $C_4H_{10}$ has the greatest number of atoms.

Which of the following has the greatest number of atoms?

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